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Find the integral between 1 and -2 for (4-x^2-3x^3)

= [4x - 1/3x³ - 3/4x⁴]¹_-2 = (4(1) - 1/3(1)³ - 3/4(1)⁴) - (4(-2) - 1/3(-2)³ - 3/4(-2)⁴) =(2 11/12) - (-8 + 8/3 - 12) =(2 11/12) - (-17 1/3) = 20 ¹/4

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Answered by Alex G. • Maths tutor

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