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Solve the ODE y' = -x/y.

we have dy/dx = -x/y , so we treat the differentials as fractions and write y dy = -x dx. Now integrating the left side with respect to y and the right side with respect to x, we have y²/2 = -x²/2 + C. Which is our final solution.

Answered by Jean-christophe M. • Maths tutor

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