A compound being analysed has the percentage composition by mass Ca = 13.9%, W = 63.9%, O = 22.2%. Calculate the empirical formula of this compound

Using rows to represent mathematical operations and a column for each compound we can draw ourselves a table:

                             Ca       W      O
%                         13.9    63.9   22.2
Atomic Mass (Ar) 40       184    16
% / (Ar)                 0.348  0.347 1.43
Ratio                    1    :     1   :   4

This produces the empirical formula Ca1W1Oor more commonly written CaWO4. We retrieve the atomic mass from our periodic table and then divide teh percentage by mass given in the question for each element by its atomic mass. We then take the smallest of these numbers and divide all the other % / (Ar) by it to produce a ratio, it doesn't matter if they aren't exact, they just have to be close to a whole number. This ratio is the ratio of elements in the empirical formula.

HD
Answered by Haydn D. Chemistry tutor

5689 Views

See similar Chemistry GCSE tutors

Related Chemistry GCSE answers

All answers ▸

Explain metallic bonding


Zinc reacts with sulphuric acid (Zn + H2SO4 --> ZnSO4 + H2). Write out two separate equations for the species that are oxidised and reduced.


What effect does temperature change have on an equilibrium reaction?


How would changing reaction vessel volume and reaction vessel temperature affect the rate of a reaction?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning