How to solve simultaneous equations?

Let's say we have two equtions: 3x + y = 8 5x + 2y = 14 In order to solve them, we need to bring one of the coefficients to the same number. Let's say we do that with y. So: 6x + 2y = 16    5x + 2y = 14 Now, we can take away the second equation from the first, which gives us: x = 2 Now we can substitute this value into any of the two equations: 6 (2) + 2y = 16 2y = 16 - 12 = 4 hence: y = 2 To verify our answers, we can substitute both values into the other equation and see if it works: 5 (2) + 2(2) = 14 10 + 4 = 14 hence the values are correct.

KW
Answered by Kamila W. Maths tutor

3700 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve algebraically the simultaneous equations (x^2) + (y^2) =25 and y - 3x = 13 (5 Marks).


Solve the following simulatenous equation to find the values of both x and y: 5x+2y=16 3x-y=14


What is the largest possible length of a pole you could fit in a room?


What is standard form?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning