Explain why the product of a nucleophilic addition to butanone does not effect plane polarized light.

The nucleophile will attack the d+ carbon atom of the carbonyl group. Since the carbonyl group is planar, attack can occur from either side with equal probability. The product of this reaction will contain a chiral centre and two chiral forms are possible as attack can occur on either side of the carbonyl group. Because attack is equally likely from either side of the carbonyl these enantiomers will be present in equal quantities.

Each enantiomer from a pair will rotate plane polarized light equally but in opposite directions. This means when plane polarized light passes through the product, the light is uneffected as the rotational effects of each enantiomer will cancel out.

PW
Answered by Philip W. Chemistry tutor

8549 Views

See similar Chemistry A Level tutors

Related Chemistry A Level answers

All answers ▸

What is the difference between pH and pKa?


The bond angle in a molecule of ammonia (NH3) is 107 degrees so why, when part of a transition metal complex is the bond angle 109.5 degrees.


Use the following data to explain why NaCl is soluble in water: ∆H = +31 kJmol-1, S(Na+(aq)) = 320.9 JK-1mol-1, S(Cl-(aq)) = 56.5 JK-1mol-1, S(NaCl(s)) = 72.1 JK-1mol-1 Are there any temperatures at which you would not expect NaCl to dissolve?


Why does the bromine become polarised in HBr during electrophilic addition


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning