Solve the equation 3x^2/3 + x^1/3 − 2 = 0

Let u = x^1/3 

The equation can therefore be written as:

3u^2+u-2=0

This can be factorised to:

(3u-2)(u+1)+0 

Therefore: u = 2/3 or u = -1 OR x^1/3 = 2/3 or x^1/3 = -1

So: x = (2/3)^3 or x = (-1)^3 

x = 8/27 or x = -1

Answered by Namita H. Maths tutor

8754 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

If cos(x)= 1/3 and x is acute, then find tan(x).


Find the first 4 term of the binomial expansion (2-4x)^5


The function f is defined for all real values of x as f(x) = c + 8x - x^2, where c is a constant. Given that the range of f is f(x) <= 19, find the value of c. Given instead that ff(2) = 8, find the possible values of c.


Calculate the first derivative of f( x)= 3x^3+2x^2-5


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences