How do you solve simultaneous equations?

Simultaneous equations have two unknowns, you need to find out one of the unkowns (eg. x) in terms of the other (e.g. y) in order to solve both unknowns. Using these two examples (x and y) we can construct an example question such as: 2x+y = 15, 2y+3x = 6 Then we choose one equation and solve for x in terms of y or y in terms of x: y=15-2x We now know what y is equal to in terms of x so we substitute that back in to the other equation: 2(15-2x) + 3x = 6 And solve for x: 30-4x + 3x = 6 x=24 And then substitute this into either of the original equations to solve for y: 2(24) + y = 15 y=63

CO
Answered by Charlie O. Maths tutor

3778 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Factorise x²+5x+6.


Three identical isosceles triangles are joined together to make a trapezium. Each triangle has base b cm and height h cm. Work out an expression, in terms of b and h for the area of the trapezium.


Calculate the length of PR. Give your answer correct to 3 significant figures (Diagram displayed on whiteboard)


I need help in Algebra as i struggle a lot with Algebra.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning