P(J>2) = P(J=0)+P(J=1) [split it up]
P(X=t)= (V^t)/t!*e^V where V=4 in this case [use the formula]
P(J>2) = 4^0/0!*e^4 + 4^1/1!*e^4
=1/e^4 + 4/e^4 = 5e^-4 which is roughly 0.0916
3495 Views
Internet Safety
Payment Security
Cyber
Essentials