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The random variable J has a Poisson distribution with mean 4. Find P(J>2)

P(J>2) = P(J=0)+P(J=1) [split it up]

P(X=t)= (V^t)/t!*e^V where V=4 in this case [use the formula]

P(J>2) = 4^0/0!*e^4 + 4^1/1!*e^4

=1/e^4 + 4/e^4 = 5e^-4 which is roughly 0.0916

NC

Answered by Nathan C. • Maths tutor

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