The random variable J has a Poisson distribution with mean 4. Find P(J>2)
P(J>2) = P(J=0)+P(J=1) [split it up]
P(X=t)= (V^t)/t!*e^V where V=4 in this case [use the formula]
P(J>2) = 4^0/0!*e^4 + 4^1/1!*e^4
=1/e^4 + 4/e^4 = 5e^-4 which is roughly 0.0916
NC
Related Maths A Level answers
All answers ▸Why does 'x' need to be in radians to differentiate 'sin x'?
Solve the simultaneous equations y = x^2 - 6x and 2y + x - 6 = 0
The curve C has the equation 4x^2 - y^3 - 4xy + 2y = 0 . The point P with coordinates (-2, 4) lies on C. Find the exact value of dy/dx at the point P.
dy/dx of 2x (3x - 1)^5