Express 3sinx - 2cosx in the form R(sin(x-a) given R>0 and 0<a<90°. Hence solve 3sinx - 2cosx = 1 in the interval 0<x<360°. What are the maximum and minimum values of 2sinx - 3cosx?

.

Answered by Calem C. Maths tutor

8488 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

If 1/(x(a-x)) is equivalent to B(1/x + 1/(a-x)), Express 'B' in terms of 'a'


Given log3(3b + 1) - log3(a-2) = -1 for a > 2. Express b in terms of a.


Supposing y = arcsin(x), find dy/dx


Core 1: Given that y = x^4 + x^2+3. Find dy/dx


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences