Solve: 3^(x^2-5x+2)=9^(x+1)

Considering that: 9=3^2. We get: 9^(x+1)=3^2*(x+1)= 3^(2x+2).

We thus solve x^2-5x+2=2x+2

which is x=0 and x=7

it will be demonstrated with more detail during the session 

PV
Answered by Petros V. Maths tutor

2918 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Work out the value of 2a^2 + b^3 when a = 5 and b = –3


Solve the simultaneous equations 2x + y = 8 and 3x + 2y = 14


Expand the brackets (x+1)(x-4)


5y = 45


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning