A ball is hit horizontally at a height of 1.2 m and travels a horizontal distance of 5.0 m before reaching the ground. The ball is at rest when hit. Calculate the initial horizontal velocity given to the ball when it was hit.
Vertically: u=0 ms-1 s=1.2 m a=9.8 ms-2 s=ut + 0.5at2 Therefore t = 0.49s Horizontally: t=0.49s s=5.0m speed = distance/time = 5.0/0.49 = 10.2 ms-1
WW
Related Physics A Level answers
All answers ▸Explain the findings from Rutherford's alpha particle scattering experiment.
Describe how the strong nuclear force between two nucleons varies with the separation of the nucleons, quoting suitable values for separation.
Do the SUVAT equations work for acceleration that changes with time?
How do I convert between eV and J