A ball is hit horizontally at a height of 1.2 m and travels a horizontal distance of 5.0 m before reaching the ground. The ball is at rest when hit. Calculate the initial horizontal velocity given to the ball when it was hit.
Vertically: u=0 ms-1 s=1.2 m a=9.8 ms-2 s=ut + 0.5at2 Therefore t = 0.49s Horizontally: t=0.49s s=5.0m speed = distance/time = 5.0/0.49 = 10.2 ms-1
WW
Related Physics A Level answers
All answers ▸You are asked to find the Young modulus for a metal using a sample of wire. *(a) Describe the apparatus you would use, the measurements you would take and explain how you would use them to determine the Young modulus for the metal.
Explain how a standing wave is set up on a string fixed at both ends.
A yacht is sailing through water that is flowing due west at 2m/s. The velocity of the yacht relative to the water is 6m/s due south. The yacht has a resultant velocity of V m/s on a bearing of theta. Find V and theta
A nail of mass 7.0g is held horizontally and is hit by a hammer of mass 0.25kg moving at 10ms^-1. The hammer remains in contact with the nail during and after the blow. (a) What is the velocity of the hammer and nail after contact?