A ball is hit horizontally at a height of 1.2 m and travels a horizontal distance of 5.0 m before reaching the ground. The ball is at rest when hit. Calculate the initial horizontal velocity given to the ball when it was hit.
Vertically: u=0 ms-1 s=1.2 m a=9.8 ms-2 s=ut + 0.5at2 Therefore t = 0.49s Horizontally: t=0.49s s=5.0m speed = distance/time = 5.0/0.49 = 10.2 ms-1
WW
Related Physics A Level answers
All answers ▸A 80kg man is hanging from two 1.5m ropes that lie at 60 degrees from the horizontal. What is the tension in each rope required to prevent the man from dropping?
In a particle accelerator, you accelerate an electron. Afterwards, you measure it's energy to be 350 keV. Tell my why you can't find the speed from this energy using your knowledge of classical mechanics.
How can an object be accelerating when it's velocity is constant, and how does centripetal acceleration work.
Steel has a density of 8030kg/m^3. Show that a steel ball with a diameter of 5cm weighs approximately 5N