A ball is hit horizontally at a height of 1.2 m and travels a horizontal distance of 5.0 m before reaching the ground. The ball is at rest when hit. Calculate the initial horizontal velocity given to the ball when it was hit.
Vertically: u=0 ms-1 s=1.2 m a=9.8 ms-2 s=ut + 0.5at2 Therefore t = 0.49s Horizontally: t=0.49s s=5.0m speed = distance/time = 5.0/0.49 = 10.2 ms-1
WW
Related Physics A Level answers
All answers ▸How do you prove Kepler's Third Law?
A person stands on top of a cliff and throws a ball with a speed of 20 m/s at an angle of 10 degrees from above the horizontal into the sea. What is the height of the cliff to 1 decimal place?
An electron is emitted from a cathode in an electron gun, with a potential difference of 150kV. Find the velocity of the electron after it is accelerated and find the De Broglie wavelength.
Find, using integration, the work done in compressing a spring by a distance x.