A ball is hit horizontally at a height of 1.2 m and travels a horizontal distance of 5.0 m before reaching the ground. The ball is at rest when hit. Calculate the initial horizontal velocity given to the ball when it was hit.

Vertically: u=0 ms-1  s=1.2 m  a=9.8 ms-2 s=ut + 0.5at2 Therefore t = 0.49s Horizontally: t=0.49s  s=5.0m speed = distance/time = 5.0/0.49 = 10.2 ms-1

WW
Answered by William W. Physics tutor

2867 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

Single electrons travelling at 550 ms^-1 are passed through a diffraction grating with a spacing between the slits of 2.5 micrometers. What would the angle between the zeroth and first maximum of the resulting interference pattern be?


A stationary particle explodes into 3: A (to the left), B and C (both to the right). B has mass m and speed 3v. C has mass 2m and speed v. A has speed 2v. What is the mass of A in terms of m?


A mass, m, is resting on a slope being slowly tilted upwards from horizontal. The static friction co-efficient is 0.3 and the dynamic friction co-efficient is 0.2: at what angle will the mass begin to slip?


Draw a diagram of the forces acting on the rocket as it flies vertically upwards, the rocket is flying through air not a vacuum (it's not in space yet!)


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences