A ball is hit horizontally at a height of 1.2 m and travels a horizontal distance of 5.0 m before reaching the ground. The ball is at rest when hit. Calculate the initial horizontal velocity given to the ball when it was hit.
Vertically: u=0 ms-1 s=1.2 m a=9.8 ms-2 s=ut + 0.5at2 Therefore t = 0.49s Horizontally: t=0.49s s=5.0m speed = distance/time = 5.0/0.49 = 10.2 ms-1
WW
Related Physics A Level answers
All answers ▸Two electrons are a distance r apart, the first electron exerts a force F on the second electron. a) What force does the second electron exert on the first? b) In terms of r, at what distance is the force that the first electron exerts on the second F/9?
Show that a mass on a spring obeys simple harmonic motion.
A particle that moves uniformly in a circular path is accelerating yet moving at a constant speed. Explain this statement.
An ice cube with a small iron ball in its centre is placed in a cup of water. 3.9 x 10-3kg of water in the cup is displaced and the volume of the ice cube is 4.0 x 10-6m3. Ice density: 1000 kg m-3 Iron density: 7800 kg m-3, what is the volume of the iron?