A ball is hit horizontally at a height of 1.2 m and travels a horizontal distance of 5.0 m before reaching the ground. The ball is at rest when hit. Calculate the initial horizontal velocity given to the ball when it was hit.
Vertically: u=0 ms-1 s=1.2 m a=9.8 ms-2 s=ut + 0.5at2 Therefore t = 0.49s Horizontally: t=0.49s s=5.0m speed = distance/time = 5.0/0.49 = 10.2 ms-1
WW
Related Physics A Level answers
All answers ▸What is meant by an excited atom?
How would you calculate the vertical and horizontal components of the velocity of an object with an initial velocity of 15m/s which is travelling upwards at an angle of 30 degrees to the horizontal?
Why is gravitational potential energy negative?
Explain how and why the diffraction pattern of electrons passing through a slit depends on their momentum.