Solve algebraically 6a + b = 16 & 5a - 2b = 19
6a + b = 16 Equation 1
5a - 2b = 19 Equation 2
Scale up one equation so both equations have same coeffient of one variable ie 2 times Equ 1
12a + 2b = 32
5a - 2b = 19
Add variables of each equation, hence eliminating variable b
17a = 51
Divide both sides by 17
a=3
Substitute a=3 into either one of the original equations
5(3) - 2b = 19
15 - 2b = 19
Subtract 15 from both sides of equation
-2b = 4
Divide both sides by -2
b = -2
Hence final answer: a=3, b=-2
EM
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