A curve C has the equation x^3 +x^2 -10x +8. Find the points at which C crosses the x axis.

Factorise: (x-2)(x+4)(x-1)

Set equal to 0: (x-2)(x+4)(x-1) = 0

Points are (2,0) (-4,0) (1,0)

Answered by William F. Maths tutor

2690 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do you calculate the angle between two vectors?


What is the equation of the tangent to the circle (x-5)^2+(y-3)^2=9 at the points of intersection of the circle with the line 2x-y-1=0


What is the tangent line to the curve y = x^3+4x+5 at the point where x = 2?


A circle has equation x^2 + y^2 - 8x - 10y + 5 = 0, find its centre and radius


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences