To differentiate a simple equation: y= 4x^3 + 7x

y = 4x^3 + 7 x

Recall: to differentiate any function of the form y = x^n

dy/dx = y' = n x^(n-1)

Hence if y = 4x^3 + 7x

dy/dx = 4 ( 3x^3 -1) + 7x^(1-1)          

= 12 x^2 + 7

YS
Answered by Yusuf S. Further Mathematics tutor

6462 Views

See similar Further Mathematics GCSE tutors

Related Further Mathematics GCSE answers

All answers ▸

If y=x^3+9x, find gradient of the tangent at (2,1).


Solve the simultaneous equations xy=2 and y=3x+5.


l1 and l2 are tangents of a circle. l1 intersects the circle at (3-√3,5) with a gradient of √3, and l2 intersects the circle at (3+√2,4+√2) with a gradient of -1. Find the centre of the circle, and hence find the radius of the circle.


Lengths of two sides of the triangle and the angle between them are known. Find the length of the third side and the area of the triangle.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences