Calculate the acceleration of particle thats velocity changes from 20ms^-1 to 40ms^-1 in 5 seconds, assuming its constant.

Acceleration is the rate of change of velocity, so we subtract the final velocity from the initial velocity and divide it by the time taken for the change. In this case the acceleration is (40-20)/5 = 4ms^-2. This means that each second, the velocity of the particle is increasing by 4ms^-1

Answered by Orlando F. Physics tutor

3414 Views

See similar Physics GCSE tutors

Related Physics GCSE answers

All answers ▸

Why are transformers used in the National Grid?


A force is applied to a box of mass 2kg so that is accelerates at 2ms^-2. Find the force acting on the box and thus calculate the work done in moving the box 10m in the direction of the force.


Describe how the forces change on a parachutist while they fall.


Can you explain the difference between distance and displacement


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences