Calculate the acceleration of particle thats velocity changes from 20ms^-1 to 40ms^-1 in 5 seconds, assuming its constant.

Acceleration is the rate of change of velocity, so we subtract the final velocity from the initial velocity and divide it by the time taken for the change. In this case the acceleration is (40-20)/5 = 4ms^-2. This means that each second, the velocity of the particle is increasing by 4ms^-1

Answered by Orlando F. Physics tutor

3371 Views

See similar Physics GCSE tutors

Related Physics GCSE answers

All answers ▸

Which renewable energy methods are the best?


What is the difference between current and voltage?


What is nuclear fusion?


Ann and Bob play on a uniform seesaw. The seesaw is 4m long and Ann and Bob weigh 600N and 800N respectively. If both Ann and Bob start at one end of the seesaw and Bob starts to walk up the seesaw at 2m/s, after how long will the seesaw turn?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences