Differentiate 2x^3+23x^2+3x+5 and find the values of x for which the function f(x) is at either at a maximum or minimum point. (Don't need to specify which is which)
f(x)=2x3+23x2+3x+5
f'(x)=6x2+46x+3
Maximum or minimum when f'(x)=0
6x2+46x+3=0
Using the Quadratic Formula: x=(-b+-squareroot(b2-4ac))/2a
x1=-0.0658
x2=-7.6
SK
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