Given: h=3t^2, work out the value of h when t=5.

We have been told that t = 5 in this particular question. So our first step is to simply 'swap out' the t in the above equation for the number 5, as we have been told they mean the same thing. This gives us: h = 3(5)^2 And now our equation looks a lot more friendly, as there are no letters! Now that follows in calculation. The only other bit of knowledge we need to remember, for all algebra problems, is the BIDMAS idea. This stands for Brackets, Indicies, Division, Multiplication, Addition and Subtraction, and represents the order in which we carry out 'operations' or adding/subtracting/timesing numbers. If you find it hard to remember, it may be worth just jotting it down on the page when you see algebra questions pop up. So using BIDMAS, and looking at the equation, we see that first we do the Indicies operation, and then the Multiplication. And so our last two steps: h = 3(25) h=75. Which is our final answer! 

Answered by Alexander D. Maths tutor

7377 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How should I present my working out?


What is the gradient of a line with the equation y=4x+5?


√ 5(√ 8 + √ 2) Can be written as "a√ 10". What is the value of a?


Solve algebraically the simultaneous equations: x^2 + y^2 = 25 and y – 3x = 13


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences