25.00cm3 of sodium hydroxide was pipetted into a conical flask. It was titrated against 0.10mol/dm3 hydrochloric acid. The mean volume of acid needed was 24.00cm3. Calculate the concentration of sodium hydroxide used in the titration.
First write out the chemical equation:
HCl + NaOH -> NaCl + H20
Next construct a table with the information we have and in what units.
Next write out what calculation triangle we need:
Number of moles = vol in dm3 X concentration = 0.0024 mol
One mole of HCl: one mole of NaOH, therefore 0.0024mol of NaOH
Concentration = no of moles / vol in dm3 = 0.096 mol/dm3 to 2dp.
MB
Related Chemistry GCSE answers
All answers ▸How does the structure of benzene differ from the pre-assumed structure of 1,3,5-cyclohexatriene? *Kekule's structure*
Explain why DNA replication is considered semi-conservative.
How can Diamond and Graphite both be made of carbon but be so different?
50.0 g of propene reacts with hydrochloric acid to produce 1-chloropropane. Calculate the percentage yield if only 54.0g is made.