25.00cm3 of sodium hydroxide was pipetted into a conical flask. It was titrated against 0.10mol/dm3 hydrochloric acid. The mean volume of acid needed was 24.00cm3. Calculate the concentration of sodium hydroxide used in the titration.

First write out the chemical equation:

​​​​​​HCl + NaOH -> NaCl + H20

Next construct a table with the information we have and in what units.

Next write out what calculation triangle we need:

Number of moles = vol in dm3 X concentration = 0.0024 mol

One mole of HCl: one mole of NaOH, therefore 0.0024mol of NaOH

Concentration = no of moles / vol in dm3 = 0.096 mol/dm3 to 2dp.

MB
Answered by Matthew B. Chemistry tutor

11685 Views

See similar Chemistry GCSE tutors

Related Chemistry GCSE answers

All answers ▸

Why is Chlorine a gas at room temperature but Sodium Chloride is a solid?


What is a mole and why is it useful?


How do I calculate the relative formula mass of FeSO4 and the number of moles, when the formula mass of O=16, S=32, Fe=56 and the mass of FeSO4= 380g


Potassium forms an ionic compound with sulfur. Describe what happens when two atoms of potassium reaction with one atom of sulfur (5 marks)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning