25.00cm3 of sodium hydroxide was pipetted into a conical flask. It was titrated against 0.10mol/dm3 hydrochloric acid. The mean volume of acid needed was 24.00cm3. Calculate the concentration of sodium hydroxide used in the titration.

First write out the chemical equation:

​​​​​​HCl + NaOH -> NaCl + H20

Next construct a table with the information we have and in what units.

Next write out what calculation triangle we need:

Number of moles = vol in dm3 X concentration = 0.0024 mol

One mole of HCl: one mole of NaOH, therefore 0.0024mol of NaOH

Concentration = no of moles / vol in dm3 = 0.096 mol/dm3 to 2dp.

MB
Answered by Matthew B. Chemistry tutor

12161 Views

See similar Chemistry GCSE tutors

Related Chemistry GCSE answers

All answers ▸

The student did another experiment using 20 cm3 of sodium hydroxide solution with a concentration of 0.18 mol/dm3 . Relative formula mass (Mr) of NaOH = 40 Calculate the mass of sodium hydroxide in 20 cm3 of this solution.


What is the charge of a nucleus?


Given the balanced equation: MgCO3 + 2HCl --> MgCl2 + H2O + CO2, if 5 grams of MgCO3 is used, what volume of CO2 is produced? (molar mass of MgCO3 is 84.3 g/mol)


Describe how carbon dioxide helps maintain temperature on Earth


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning