25 cm^3 of a solution of known 0.2M HCl is neutralised by titration by 21.5cm^3 of NaOH solution. Calculate then concentration of the NaOH solution to 3dp.

Recall n = c *(v/1000) if the volume is in Cm3.

Now, n(HCl)= 0.2 x (25.0/1000) 

n(HCl) = 5x10-3

Since the relationship stoichiometrically is 1:1 (H+:OH-), we can infer that 

n(NaOH) = 5x10-3 

and by rearranging to c=n/(v/1000)

c(NaOH) = (5x10-3) / (21.5/1000)

c(NaOH) = 10/43 moldm-3 and to 3dp, c(NaOH) = 0.233moldm-3

Answered by Will F. Chemistry tutor

2574 Views

See similar Chemistry GCSE tutors

Related Chemistry GCSE answers

All answers ▸

Describe how to find the concentration of an alkali using an acid of a known concentration.


How does column chromatography work? (A-Level Chemistry)


The reaction for the Haber process is shown below. N2(g) + 3H2(g) ⇌ 2NH3(g) What will be the effect of increasing the pressure on the amount of ammonia present at equilibrium? [1 mark]


Sodium and sodium chloride can both conduct of electricity under cetain conditions. Describe and explain the method of conduction for each species. (3)


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences