Given that Sin(A) = 1/sqrt(3), show that Tan(A) = 1/sqrt(2)
Using: Tan(x) = Sin(x)/Cos(x)
Using: Cos(x) = sqrt(1-Sin2(x))
Cos(A) = sqrt(1-Sin2(A)) = sqrt(1-1/3) = sqrt(2)/sqrt(3)
Therefore: Tan(A) = Sin(A)/Cos(A) = (1/sqrt(3))/(sqrt(2)/sqrt(3)) = 1/sqrt(2)
SH
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