Given that Sin(A) = 1/sqrt(3), show that Tan(A) = 1/sqrt(2)

Using: Tan(x) = Sin(x)/Cos(x)

Using: Cos(x) = sqrt(1-Sin²(x))

Cos(A) = sqrt(1-Sin²(A)) = sqrt(1-1/3) = sqrt(2)/sqrt(3)

Therefore: Tan(A) = Sin(A)/Cos(A) = (1/sqrt(3))/(sqrt(2)/sqrt(3)) = 1/sqrt(2)