find dy/dx for the equation y = 6x ^(1/2)+x+3

Here you are being asked to differentiate. When differentiating, you times the value of x by its power and then subtract 1 from the power. So for this question you times 6x^(1/2) by 1/2 and then subtract 1 from its power, this gives you 3x^(-1/2). x is the same as x^1 so by following the same rule, this leaves you with x^0. Any number to the power of 0 is 1, therefore, x goes to 1. And finally the 3, it has no x term and so, therefore, is 0. Put all together the answer is dy/dx=3x^(-1/2)+1