find dy/dx for the equation y = 6x ^(1/2)+x+3

Here you are being asked to differentiate. When differentiating, you times the value of x by its power and then subtract 1 from the power. So for this question you times 6x^(1/2) by 1/2 and then subtract 1 from its power, this gives you 3x^(-1/2). x is the same as x^1 so by following the same rule, this leaves you with x^0. Any number to the power of 0 is 1, therefore, x goes to 1. And finally the 3, it has no x term and so, therefore, is 0. Put all together the answer is dy/dx=3x^(-1/2)+1

GB
Answered by George B. Maths tutor

5022 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do you differentiate 5x


The rate of growth of a population of micro-organisms is modelled by the equation: dP/dt = 3t^2+6t, where P is the population size at time t hours. Given that P=100 at t=1, find P in terms of t.


Why is the inverse of a gradient -1/x?


Express 4x/(x^2-9)-2/(x+3) as a single fraction in its simplest form


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning