Where do the graphs of y=3x-2 and y=x^2+4x-8 meet?
In order to find the points where these functions meet, we can equate them to get 3x-2 = x^2+4x-8 .
Subtraction (3x-2) from both sides, we get x^2+x-6 =0 which we can factorise to get (x+3)(x-2)=0
Therefore x=-3 or x=2 , and we can then get the values of y from this.
So the final answers are (-3, -11) and (2,4)
HS
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