Where do the graphs of y=3x-2 and y=x^2+4x-8 meet?

In order to find the points where these functions meet, we can equate them to get 3x-2 = x^2+4x-8 .

Subtraction (3x-2) from both sides, we get x^2+x-6 =0 which we can factorise to get (x+3)(x-2)=0

Therefore x=-3 or x=2 , and we can then get the values of y from this.

So the final answers are (-3, -11) and (2,4)