Find the location of the turning point of the following curve, y = x^2 + 6x - 7
Turning point is when dy/dx = 0
if y= x2 + 6x - 7
dy/dx = 2x + 6
at turning point: 2x + 6 = 0
therefore: 2x = - 6
x coordinate: x = - 3
substitute into y to find y coordinate: y = (-3)2 + 6(-3) -7
therefore: y = 9 -18 -7
y coordinate: y = -16
location of turning point: (-3,-16) //
HM
