Find the derivative with respect to x and the x-coordinate of the stationary point of: y=(4x^2+1)^5

y=(4x^2+1)^5                        y=u^5          u=4x^2+1

                                             y’=5u^4   (wrt u)  u’=8x

y’=40x(4x^2+1)^4

y’=40x(4x^2+1)^4=0             x=0  (x^2+1>0)

                           

EB
Answered by Ellie B. Maths tutor

3740 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

A curve has equation y = e^x + 10sin(4x), find the value of the second derivative of this equation at the point x = pi/4.


Find the stationary pointsof the following: (y = x^3 - x^2 -16 x -17) and determine if each point is a maximum or minimum.


Find d^2y/dx^2 for y=4x^4−3x^3−6x^2+x


Find the values of x and y for which dy/dx = 0 in y= x^3 - 4x^2 - 3x +2


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences