Find the derivative with respect to x and the x-coordinate of the stationary point of: y=(4x^2+1)^5

y=(4x^2+1)^5                        y=u^5          u=4x^2+1

                                             y’=5u^4   (wrt u)  u’=8x

y’=40x(4x^2+1)^4

y’=40x(4x^2+1)^4=0             x=0  (x^2+1>0)

                           

EB
Answered by Ellie B. Maths tutor

4150 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Write 5cos(theta) – 2sin(theta) in the form Rcos(theta + alpha), where R and alpha are constants, R > 0 and 0 <=alpha < 2 π Give the exact value of R and give the value of alpha in radians to 3 decimal places.


Find the value of dy/dx at the point where x = 2 on the curve with equation y = x^ 2 √(5x – 1).


How do I calculate where a function is increasing/decreasing?


Solve ∫(x+2)/(2x^2+1)^3 dx


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning