Given the Earth orbits the Sun at a distance of 1.49*10^11m with Me = 5.97*10^24kg and Msolar = 1.99*10^30, what is the gravitational force between the Earth and Sun?

Using F = Gm1m2/r^2 and substituting in the values, we get F = 3.57*10^22N.

AS

Related Physics A Level answers

All answers ▸

Draw the electric field lines produced by a negative point charge and calculate the electric field strength at a distance of 50mm from a point charge of size -30nC.


A geostationary satellite is orbiting Earth, a) What is meant by a geostationary orbit? b) Calculate the height at which the satellite orbits above the surface of the Earth. The radius of the Earth is 6400km and its mass is 6x10^24 kg.


Newton's Law of Gravitation states: F=GMm/r^2, where G is the gravitational constant (6.67×10−11m^3kg^−1s^−2). Kepler's Third Law, states t^2=kR^3. The mass of the sun is 1.99x10^30kg. Find the value of k and its units


Why are fringes are formed in the Young double slit experiment?