Can you talk me through how to solve problems on projectiles? I always get confused

The strategy is to consider the horizontal and vertical components of the motion separately, and use the equations of motion in each direction. A few things to remember are: the vertical acceleration is always -9.8 ms-2 (due to gravity), the projectile will continue to move upwards until the vertical component of its velocity is zero, the horizontal acceleration is always zero and the horizontal velocity is constant. 

do you remember what the equations of motion are? 

v = u + at, 2as = v2 - u2 and s = ut + ½at2

There are various quantities that you are commonly asked to find.

1) Time to the highest point: use v = u + at vertically, with v = 0

2) Greatest vertical height: use 2as = v2 - u2 vertically, with v = 0, or use s = ut + ½at2 if the time is known

  1. Time taken for it to reach a particular height: use s = ut + ½at2 vertically (if it is returning to the same height at which it started - eg returning to the ground - take s = 0)

  2. Total horizontal distance travelled find the time taken for it to finish its journey (as above), then use s = ut horizontally

Do these rules make sense? Now lets look at some sample questions. 

Answered by Maham K. Physics tutor

2301 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

From the 2016 OCR B paper A ball is thrown at an angle of 30 Degrees to the horizontal. The initial kinetic energy of the ball is K. Air resistance is negligible. What is the kinetic energy of the ball at the maximum height.


What is a stationary wave?


A particle that moves uniformly in a circular path is accelerating yet moving at a constant speed. Explain this statement.


Why is gravitational potential energy negative?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences