A spacecraft needs to be slowed down from a speed of 96m/s to 8.2m/s. This can be done by firing an object as the spacecraft is moving. If the mass of the spacecraft is 6730kg and the object is 50kg, calculate the velocity of the ejected object.

As we have there is object being fired out of the front of the spaceship we know the ship will have a lower velocity than before using the conversation of momentum. "The total momentum of a system is the same before and after providing no external forces are present" and that momentum is the product of the velocity and mass of an object. Therefore, we simply calculate the momentum before ejection. i.e. total mass (mass of ship plus object, 6730kg+50kg=6780kg) multiped by originally velocity, 96m/s. Giving the momentum at the start of 650880kgm/s. next we consider the total momentum after, which the new momentum of the ship (smaller now as it slowed down) plus the momentum of the object. New momentum if the ship is the new velocity (8.2m/s) multiped by its mass (6730kg). 55186kgm/s. and the object will be its mass (50kg) multiped by x m/s. 50x kgm/s. the sum if these two values will the starting momentum.

650880 = 55186 + 50x

50x = 595694

X = 11913.88m/s

This means the ejected object will need velocity of 11913.88 m/s.

BQ
Answered by Ben Q. Physics tutor

2241 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

A) Draw field lines around a positive point particle. B) How does a faraday cage prevent the people within it recieving a electric shock ?


Asteroid of mass 10^16 kg is travelling in the equatorial plane of Earth. It hits the surface at 45°. After the impact the day shortens by 1% (15 mins). How fast was the asteroid - comment? Neglect effects of atmosphere. Consider only inelastic collision.


Calculate the threshold wavelength for a metal surface with work function of 6.2 eV.


Describe the process of nuclear fission is induced


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning