ABC and DEF are similar isoceles triangles. AB=BC=5cm, AC=6cm, DF=12cm. What is the area of DEF?

We first split ABC into two right-angled triangles. We name the midpoint of AC, M. AM=1cm, and BM=sqrt(52-32)=4 by Pythagoras. The area of ABC =1/2ACBM=1/264=12. We can see that the side lengths of DEF are greater than the side lengths of ABC by a factor of two. The area is therefore greater than ABC by a factor of 22=4. So the area of DEF=4*12=48

Answered by Peter G. Maths tutor

3093 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do you solve a quadratic equation e.g. x^2 - 5x - 14 = 0?


Solve the following quadratic inequality: 6x^2 -x -35 < 0


There are 10 boys and 20 girls in a class. The class has a test. The mean mark for all the class is 60. The mean mark for the girls is 54. Work out the mean mark for the boys.


Express 112 as a product of it's prime factors.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences