2.11g of MgCl2 is added to 30cm3 of water. Find the concentration of chloride ions in the solution.

M_r of MgCl₂ = 24.3 + 2(35.5) = 95.3 Moles added = 2.11/95.3 = 0.02214 Mol of cl^-  added = 20.02214 = 0.04428 Conc = 0.04428/(3010^-3) = 1.48 moldm^-3