Line AB, with equation: 3x + 2y - 1 = 0, intersects line CD, with equation 4x - 6y -10 = 0. Find the point, P, where the two lines intersect.

Let eqn. 1 be: 3x + 2y - 1 = 0  & Let eqn. 2 be: 4x - 6y -10 = 0

Multiply eqn. 1 by a factor of 3, and add the two eqautions together. (This eliminates y from the equation)

This gives: 9x + 6y - 3 = 0

+                4x - 6y - 10 =0

This gives the equation: 13x - 13 = 0, so 13x = 13, and therefore x =1

Substitute this value of x into either eqn. 1 or eqn. 2. (I will use eqn. 1 for this example)  3(1) + 2y - 1 = 0. This can be rearranged to give 2y = -2, and hence y = -1.

Therefore, point P is at (1, -1).

Answered by Kris S. Maths tutor

3458 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

f(x)=x^3 + x^2 -10x +8 show that (x-1) is a factor of f(x), Factorise f(x) fully , sketch the graph of f(x)


A particle is moving in the with acceleration (2t - 3) ms^-2 and initial velocity 2ms^-1. Find the distance travelled when the velocity has reached 12ms^-1.


Find the point of intersection of the lines y=2x-7 and 4y-2=3x


How can we simplify sqrt(48) - 6/sqrt(3) ?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences