Using the quadratics formula find the two solutions to x^2 + 3x + 2 = 0.

x1 = (-b + (b2 - 4ac)1/2)/2a and x2 = (-b - (b2 - 4ac)1/2)/2a. So with the values a = 1, b = 3 and c = 2: x1 = (-3 + (32 - 8)1/2)/2 and x2 = (-3 - (32 - 8)1/2)/2, x1 = (-3 + 1)/2 = -1 and x2 = (-3 - 1)/2 = -2. 

Answered by Rebecca D. Maths tutor

3269 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

A rectangular path has perimeter of 240m. If the rectangle is split lengthways, two paths of 160m are formed. Work out the lengths of the sides of the original path.


Factorising and Expanding Brackets


Solve for y: 5(y – 2) + 2(y – 3) = 19


(a) The equation of a line L is 2x-3y=6. Find the gradient of L. (b) Find the equation of the line which is parallel to L and passes through the point (6,9)


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences