How do i solve two linear simultaneous equations 2x+y=7 & 3x-y=8 ?

To start with, try and spot whether or not two of the coeffecients (numbers next to the letters) are the same for either question (i.e. could be a 3x in one equation and a 3x in the other). This also works if the number is the same but the sign is different (i.e. 2x and -2x). As one equation contains a y, and the other contains a -y, you need to add the two equations together to eliminate the y, leaving 5x=15.

Dividing through by 5 leaves x=3, and if you substitute this back into either of the original equations you get that y=1.

TB

Related Maths A Level answers

All answers ▸

Use the substitution u = 2^x to find the exact value of ⌠(2^x)/(2^x +1)^2 dx between 1 and 0.


Using the substitution of u=6x+5 find the value of the area under the curve f(x)=(2x-3)(6x+%)^1/2 bounded between x=1 and x=1/2 to 4 decimal places.


Find the general solution of the equation tan(2x + pi/2) = SQRT(3), giving your answer for x in terms of π in a simplified form.


Integrate 2x^5 - 1/4x^3 - 5