A child is standing on a walkway that is moving at 2 metres per second and decides to turn around and walk back to the start at 2 metres per second. Explain why the child cannot reach the start of the walkway at this speed.

Assuming that the walkway is moving in a positive direction, the child is walking in the opposite direction to it and is therefore walking in the negative direction. Both the child and the walkway have velocity, but their velocities are opposite since the direction they are moving in are directly opposite to eachother, however since they are moving at the same speed, the velocities will cancel out: -2+2=0. This result shows that in fact the child will not actually move and seem to be walking on the spot. 

MS
Answered by Merry S. Physics tutor

1981 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

How would you calculate the vertical and horizontal components of the velocity of an object with an initial velocity of 15m/s which is travelling upwards at an angle of 30 degrees to the horizontal?


What is the difference between accuracy and precision?


Explain what is meant by tensile stress and tensile strain.


This Question is a multi-parter but all around the same scenario. Similar to an end of paper A-level physics question.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning