Given y = x^3 + 4x + 1, find the value of dy/dx when x=3

To differentiate this equation, you must bring the power of each x term down to the front and reduce the power of x by 1, with constants disappearing:

dy/dx = 3x3-1 + (41)*x1-1 =  3x2 + 4

To find the value of this when x=3, simply substitute this value into the equation for dy/dx:

dy/dx = 3(3)2 + 4 = 27 + 4 = 31

This value represents the gradient of the line y = x3+4x+1 when x=3.

Answered by Florence H. Maths tutor

9479 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

The second and fourth term of a geometric series is 100 and 225 respectively. Find the common ratio and first term of the series. Round your answer to 2 d.p if necessary


Differentiate x^x


How would the integral ∫x^2sin2xdx be solved using integration by parts?


Integrate (x^2+4x+13)/((x+2)^2)(x-1) dx by using partial fractions


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences