sin(x)/(cos(x)+1) + cos(x)/(sin(x)+1) = 1

sin^2(x) + sin(x) + cos^2(x) + cos(x) = cos(x)sin(x) + cos(x) + sin(x) +1

(sin^2(x) + cos^2(x) =1) Therefore;

1 +sin(x) + cos(x) = cos(x)sin(x) + sin(x) +cos(x) +1

Cancelling out on both sides

cos(x)sin(x) = 0

Solution: cos(x)=0 x=pi/2 + kpi sin(x)=0 x= 0+ kpi 

Answered by James O. Maths tutor

3353 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Use the addition formulas: sin(x+y)=sin(x)*cos(y)+sin(y)*cos(x), cos(x+y)=cos(x)*cos(y)-sin(x)*sin(y) to derive sin(2x), cos(2x), sin(x)+sin(y).


How do you integrate tan^2(x)?


Integrate the function y = 2x^2 + 3x + 8 with respect to x.


Express 8/((root3) -1)) in the form a(root3) +b, where a and b are integers.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences