Rearrange the following making a the subject: (a+2)/5 = 3a+b

(a+2)/5 = 3a+b  ...first, we need to multiply both sides by 5

a + 2 = 5 (3a + b)  ....to be able substract 3a from the right side we need to remove the bracket. We multiply the bracket by 5.

a + 2 = 15a + 5b  ...now we need to make sure all element containing a are on the same side of the equation. We do -a and -5b

a + 2 -a -5b = 15a + 5b - a - 5b ...to make it easier to imagine, we can write the equation like this

2 - 5b = 14a  ...Finally, we need to make 1a the subject so we devide the equation by 14

(2-5b) / 14 = a  ...Congratulations!!!

KR
Answered by Katerina R. Maths tutor

3593 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

If 5x + 3y = 27 and 6x - 2y = 10, find x and y


What are the two roots of the equation (4x-8)(x-3) = 0?


expand and simplify (x+3)(x-7)


Factorise x^2+7x+10 to find the roots of the equatino x^2+7x+10=0


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning