solve (2x+3)/(x-4) - (2x-8)/(2x+1) = 1 leave answer in fraction form

times both sides by both denominators

= (2x+3)(2x+1) - (2x-8)(x-4) = (2x+1)(x-4)

times out brackets

= (4x2 + 8x +3) - (2x2 -16x +32) = 2x2 -7x -4

simplify

= 2x2 +24x -29 = 2x2 -7x -4 

bring x's to one side 

= 31x = 25

solve for x

x= 25/31

AH
Answered by Amber H. Maths tutor

3302 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

how do I solve a quadratics equation


Prove that the square of an odd number is always 1 more than a multiple of 4


The equation the line L1 is y=3x-2 and the equation of line L2 is 3y-9x+5=0. Show that these two lines are parallel.


How to factorise x^2 + 6x +5


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning