solve (2x+3)/(x-4) - (2x-8)/(2x+1) = 1 leave answer in fraction form

times both sides by both denominators

= (2x+3)(2x+1) - (2x-8)(x-4) = (2x+1)(x-4)

times out brackets

= (4x2 + 8x +3) - (2x2 -16x +32) = 2x2 -7x -4

simplify

= 2x2 +24x -29 = 2x2 -7x -4 

bring x's to one side 

= 31x = 25

solve for x

x= 25/31

Answered by Amber H. Maths tutor

2758 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Write 16*8^2x as a power of 2 in terms of x.


How would you simplify this: ((4x+1)/4)+((1-3x)/3)


How do I solve a simultaneous equation like this: 2x-5y=3, 3x+2y=14 ?


Find the zeroes of the quadratic polynomial x^2 + 8x + 15.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences