Find, w.r.t to x, both the derivative and integral of y=6*sqrt(x)

Understand the question:

'w.r.t' stand for 'with respect to', so the qestions is asking for the dericative and integral to be calcuated in terms of x - so find dy/dx and (integral sign) y dx. 

Sqrt(x) is the same as x1/2

Deriative

Bring power to the front and decrease the power by one: dy/dx = 61/2x(1/2)-1 = 3x-1/2

Integral

Increase the power by one and divide by the new power: I = 6/((1/2)+1)*x(1/2)+1 = 4x3/2 + C

IF YOU ARE DOING A DEFINATE INTEGRAL (ONE WITHOUT LIMITS) NEVER FORGET TO PUT + C (PLUS CONSTANT. This is a very easy way to drop a mark.

JR
Answered by Jake R. Maths tutor

5223 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find dy/dx when y = 2ln(2e-x)


Polynomial long division, how do I do it?


Use integration by parts to integrate ∫ xlnx dx


Given that: y = 3x^2 + 6x^1/3 + (2x^3 - 7)/(3x^1/2), x > 0 Find dy/dx, give each term in its simplest form


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning