Find, w.r.t to x, both the derivative and integral of y=6*sqrt(x)

Understand the question:

'w.r.t' stand for 'with respect to', so the qestions is asking for the dericative and integral to be calcuated in terms of x - so find dy/dx and (integral sign) y dx. 

Sqrt(x) is the same as x1/2

Deriative

Bring power to the front and decrease the power by one: dy/dx = 61/2x(1/2)-1 = 3x-1/2

Integral

Increase the power by one and divide by the new power: I = 6/((1/2)+1)*x(1/2)+1 = 4x3/2 + C

IF YOU ARE DOING A DEFINATE INTEGRAL (ONE WITHOUT LIMITS) NEVER FORGET TO PUT + C (PLUS CONSTANT. This is a very easy way to drop a mark.

JR
Answered by Jake R. Maths tutor

4263 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

What is the product rule in differentiation?


y = 4x/(x^2+5). a) Find dy/dx, writing your answer as a single fraction in its simplest form. b) Hence find the set of values of x for which dy/dx < 0


What are the main factors when deciding whether or not the Poisson distribution is a suitable model?


Integrate xlnx with respect to x


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences