Solve the simultaneous equations: 6a + b = 16 and 5a - 2b = 19

Rearrange the first equation to give b as the subject.

b = 16 - 6a

Then substitute that equation for b into the second equation.

5a - 2(16 - 6a) = 19

Simplify this equation (remembering to take account of the double negative) and solve for a.

5a - 32 + 12a = 19

17a - 32 = 19

17a = 51

a = 3

Substitute the value of a into the previous equation for b and solve.

b = 16 - (6 x 3)

b = 16 - 18

b = -2

FL
Answered by Francesca L. Maths tutor

4441 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

I don't understand how to expand and simplify brackets such as (x-3)(x+5)


work out the area of a trapezium where the height is 4mm, the top length is 8mm and the bottom length is 12.5mm


20% of 14,000


5(7x + 8) + 3(2x + b) ≡ ax + 13 Find the values of a and b


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning