(3 + root(a))(4 + root(a)) = 17 + k(root(a)) where a and k are positive integers. Find the value of a and the value of k.

Let's open out the bracket using the FOIL method (first, outside, inside, last):

(3 + root(a))(4 + root(a)) = 12 + 3root(a) + 4root(a) + (root(a))2 = 12 + 7root(a) + a.

Since the answer 17 + k(root(a)) is in the form of an integer + surd, we must equate the integers and surds of 12 + 7root(a) + a     with       17 + k(root(a)).

Therefore, 12 + a = 17       so     a = 5

7root(a) = k(root(a))           so     k = 7.

AJ
Answered by Abhinav J. Maths tutor

9858 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Write down the value of 169^1/2 (one hundred and sixty nine to the power of a half)


Express 56 as the product of the its prime factors.


a)Work out the total surface area of this cuboid (3cm x 4cm x 2cm). b) The cuboid has density 7g/cm^3, what is the mass of the cuboid?


Expand (x+4)(x+3).


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning