Factorise and solve the quadratic equation x^2 + 6x + 8 = 0

Theory

Problems like this need to be broken down into steps: i) Factorise, ii) solve and iii) check. The aim of this question is to find values of x which satisfy the quadratic equation, i.e. when we substitute our solutions of x into x2 + 6x + 8, we get zero. Quadratic factorisation means converting a quadratic equation (an equation with x2 in, as provided in the question) into the form: (ax+b)(cx+d) = 0, where a, b, c and d are numbers to be determined. Since 0x0 = 0 we can assume (ax+b) = 0 and (cx+d) = 0 and solve for x in both cases.

Solution

i) Factorise

We want to convert out quadratic equation into (ax+b)(cx+d) = 0. Firstly, multiply out the brackets using the F.O.I.L method – multiply the First terms in each bracket, e.g. ax times cx to give acx2, the Outer terms, Inner terms and Last terms, and finally add them all together. This returns acx2 + adx + bcx + bd = 0, which we can simplify to ax2 + (ad+bc)x + bd = 0.

Now we compare our quadratic equation x2 + 6x + 8 = 0 to acx2 + (ad+bc)x + bd = 0.

Notice that the coefficient (number in front) of the x2 term is 1 in the first equation and ac in the second equation. Hence, ac = 1. We can now set a = 1 and c = 1.

Next, we have (ad + bc) = 6. Using a = 1 and c = 1, this can be simplified to d + b = 6. Similarly, bd = 8.

By trial and error, we can find two numbers that multiply together to make 8 and add together to make 6. These are d = 4 and b = 2.

Substituting a = 1, b = 2, c = 1 and d = 4 into (ax+b)(cx+d) = 0 our factorised quadratic equation is: (x+2)(x+4) = 0.

ii) Solve

Since both brackets in (x+2)(x+4) = 0 are just two numbers multiplied together, both brackets must separately equal zero. Therefore, x+2 = 0 and x+4 = 0, which means x = -2 and x = -4.

iii) Check

Substituting x = -2 and x = -4 into our original equation should return zero:

When x = -2,

(-2)2 + 6(-2) + 8 = 4 – 12 + 8 = 0

When x = -4,

(-4)2 + 6(-4) + 8 = 16 – 24 + 8 = 0

This is correct, and our solution is: x = -2 and x = -4.

With practise this becomes much easier and steps can be skipped. For example, we would skip straight to comparing x2 + 6x + 8 = 0 to acx2 + (ad+bc)x + bd = 0, and guessing values for a, b, c and d.

TD

Related Maths GCSE answers

All answers ▸

In a bag of 72 red and green marbles, 5/9 are green. What is the number of red marbles in the bag?


A class of pupils were asked about how they travelled to school on a particular day. 1/6 of the pupils were driven to school in a car. 2/5 of the pupils took the bus. The rest of the pupils walked to school. Calculate the fraction of pupils who walk


Insert one pair of brackets so that this calculation is correct; 3 x 6 + 5 - 1 = 32


In one month, Karen takes the bus to school on 25 days. On 5 of these days the bus is late. What fraction of the days Karen takes the bus to school is the bus late? (Give your answer in the simplest form)