The mass, m grams, of a substance is increasing exponentially so that the mass at time t hours is m=250e^(0.021t). Find the time taken for the mass to double in value.

All exponential equations can be reduced to the form m=m0ekt, where m0 is the initial mass. This means for our equation the initial mass is 250g. If the mass has doubled in size, then m now equals 2*250 = 500g. Plugging this into our exponential equation gives us 500=250e0.021t , which we can then work through as follows to re-arrange for t:

e0.021t = 500/250 = 2

0.021t = ln(2)

t = ln(2) / 0.021 = 33.0070086 = 33.0 hours (3 significant figures)

TJ
Answered by Tom J. Maths tutor

8559 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find all solutions to the equation 8sin^2(theta) - 4 = 0 in the interval 2(pi) < (theta) < 4(pi)


Simplify: (3x+8)/5 > 2x + 1


Show that 2tan(th) / (1+tan^2(th)) = sin(2th), where th = theta


Find values of y such that: log2(11y–3)–log2(3) –2log2(y) = 1


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning