The mass, m grams, of a substance is increasing exponentially so that the mass at time t hours is m=250e^(0.021t). Find the time taken for the mass to double in value.

All exponential equations can be reduced to the form m=m0ekt, where m0 is the initial mass. This means for our equation the initial mass is 250g. If the mass has doubled in size, then m now equals 2*250 = 500g. Plugging this into our exponential equation gives us 500=250e0.021t , which we can then work through as follows to re-arrange for t:

e0.021t = 500/250 = 2

0.021t = ln(2)

t = ln(2) / 0.021 = 33.0070086 = 33.0 hours (3 significant figures)

Answered by Tom J. Maths tutor

7475 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

find x: e^(3x-9) = 8


When and how do I use integration by parts?


The curve C has equation (4x^2-y^3+3^2x)=0. The point P (0,1) lies on C: what is the value of dy/dx at P?


Integral of Cosec(x)/Sec(x) (i.e. Use of trignometric identities)


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences