What is the indefinite integral ∫5exp(3-4x)dx ?

∫ 5e^3-4x dx=5∫e³ e^-4x dx=5e³ ∫e^-4x d=5e³ [(-1/4)e^-4x ]=-(5/4)e³e^-4x =-(5/4)e^3-4x