What is the indefinite integral ∫5exp(3-4x)dx ?

∫ 5e3-4x dx=5∫ee-4x dx=5e∫e-4x d=5e[(-1/4)e-4x ]=-(5/4)e3e-4x =-(5/4)e3-4x

Answered by Alexandros M. Maths tutor

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