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What is the indefinite integral ∫5exp(3-4x)dx ?

∫ 5e^3-4xdx=5∫e³e^-4xdx=5e³∫e^-4xd=5e³[(-1/4)e^-4x]=-(5/4)e³e^-4x=-(5/4)e^3-4x

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Answered by Alexandros M. • Maths tutor

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