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What is the indefinite integral ∫5exp(3-4x)dx ?

∫ 5e3-4x dx=5∫e3 e-4x dx=5e3 ∫e-4x d=5e3 [(-1/4)e-4x ]=-(5/4)e3e-4x =-(5/4)e3-4x

Answered by Alexandros M. • Maths tutor

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