When (x – 2)^2 + 7 has a minimum value, what is the value of x?

First, expand (x-2)2:

= (x-2)(x-2),

= x2 - 2x - 2x + 4

= x2 - 4x + 4

Add on the +7:

= x2 - 4x + 11

complete the square

= (x - 2)2 - 4 + 11

= (x - 2)2 + 7

when the graph has a minumum value, (x - 2) = 0,

so x = 2

Answered by Tom L. Maths tutor

5412 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the simultaneous equations: 4x + y = 25, x - 3y = 16


Northern Bank has two types of account. Both accounts pay compound interest. Cash savings account: Interest 2.5% per annum Shares account: Interest 3.5% per annum Ali invests £2000 in the cash savings account. Ben invests £1600 in the shares account.


Solve 4x - 6 < 2x + 5


Expand and and simplify (x^2 + 7) (x - 1)


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences