Expand (2x+3)^4

We will you use Pascal's triangle in order to find coefficients:         1        1  1       1 2 1     1 3  3 1    1  4  6  4  1 so, our coefficients will be 1,4,6,4,1 now, let's expand: (2x+3)4=(2x)4+4*(2x)33+6(2x)232+4(2x)*33+34=16x4+96x3+216x2+216x+81 (2x+3)4=116x4+96x3+216x2+216x+81

CP
Answered by Cezar P. Further Mathematics tutor

3294 Views

See similar Further Mathematics GCSE tutors

Related Further Mathematics GCSE answers

All answers ▸

Given y=x^3-x^2+6x-1, use diffferentiation to find the gradient of the normal at (1,5).


write showing all working the following algebraic expression as a single fraction in its simplest form: 4-[(x+3)/ ((x^2 +5x +6)/(x-2))]


Solve x^(-1/4) = 0.2


Solve the following simultanious equations: zy=28 and 2z-3y=13


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning