Why is the integral of a function the area?

Say you have two functions, A and B, and A is the gradient of B. That is to say, A is as high as B is steep (at any point). Equally, A is as high as the rate of change of B (at any point). Now let’s say we want to find a function that tells us the area under the curve A. Since the area under the curve A will increase as fast as A is high (think: if A is really high, then moving even a little along in x will result in a massive change in area still), we must be looking for a function which is increasing as fast as A is high. Rephrasing this a little bit, we want a function whose gradient (rate of increase) is as high as A is, which from our definition of a derivative is exactly the function B since A is the gradient of B. Thus, to find the area under a function A, we are always looking for the function B, which when differentiated, produces A, and so is the integral of A.

MC
Answered by Madison C. Maths tutor

3050 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Rationalise the denominator of \frac{6}{\sqrt{2}}.


What is the centre and radius of the circle with the equation x(x-2)+y(y+6)+4=0 ?


If I have a picture of a graph f(x), how can I draw what |f(x)| and 3f(x-2) look like?


The curve y = 4x^2 + a/ x + 5 has a stationary point. Find the value of the positive constant a given that y-ordinate of the stationary point is 32.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning