Find the area of the surface generated when the curve with equation y=cosh(x) is rotated through 2 pi radians about the x axis, with 2<=x<=6

Use the formula for the surface area of revolution, which requires dy/dx. So find dy/dx = sinh(x) and substitute dy/dx and y into the formula with the limits provided in the question (2 and 6). Then evaluate the integral and the answer should be 2pi * (1/4sinh(12) - 1/4sinh(4) + 2).

JH
Answered by Jakub H. Further Mathematics tutor

3939 Views

See similar Further Mathematics A Level tutors

Related Further Mathematics A Level answers

All answers ▸

I don't know what I am doing when I solve differential equations using the integrating factor and why does this give us the solutions it does?


Does the following matrix A = (2 2 // 3 9) (upper row then lower row) have an inverse? If the matrix A^2 is applied as a transformation to a triangle T, by what factor will the area of the triangle change under the transformation?


Why is the argument of a+bi equal to arctan(b/a)?


Find all the cube roots of 1


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences