Find the area of the surface generated when the curve with equation y=cosh(x) is rotated through 2 pi radians about the x axis, with 2<=x<=6
Use the formula for the surface area of revolution, which requires dy/dx. So find dy/dx = sinh(x) and substitute dy/dx and y into the formula with the limits provided in the question (2 and 6). Then evaluate the integral and the answer should be 2pi * (1/4sinh(12) - 1/4sinh(4) + 2).
JH
Answered by Jakub H. • Further Mathematics tutor
5373 Views
See similar Further Mathematics A Level tutorsRelated Further Mathematics A Level answers
All answers ▸By using an integrating factor, solve the differential equation dy/dx + 4y/x = 6x^-3 (6 marks)
Differentiate: y=x^x
Using de Moivre's theorem demonstrate that "sin6x+sin2x(16(sinx)^4-16(sinx)^2+3)"
A curve has polar equation r = 1 + cos THETA for 0 <= THETA <= 2Pi. Find the area of the region enclosed by the curve