Find the area of the surface generated when the curve with equation y=cosh(x) is rotated through 2 pi radians about the x axis, with 2<=x<=6

Use the formula for the surface area of revolution, which requires dy/dx. So find dy/dx = sinh(x) and substitute dy/dx and y into the formula with the limits provided in the question (2 and 6). Then evaluate the integral and the answer should be 2pi * (1/4sinh(12) - 1/4sinh(4) + 2).

Related Further Mathematics A Level answers

All answers ▸

The set of midpoints of the parallel chords of an ellipse with gradient, constant 'm', lie on a straight line: find its equation; equation of ellipse: x^2 + 4y^2 = 4


Express f(x) = ln(x+1) as an infinite series in ascending powers of x up to the 3rd power of x


Find y in terms of x for the equation 2x(dy/dx) + 4y = 8x^2


Solve x^3=1 giving all the roots between -pi<=theta<=pi in exponential form


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences