The differential of ln(x) is x^-1 or 1/x. Because we have x^3 + 2 inside the bracket we have to differentiate this term also and multiply this with the other term. For example, d/dx of x^3 +2 is equal to 3x^2. Following on from previously we differentiate ln(x^3 + 2) we get 1/(x^3 + 2). However this isn't complete as we need to multiply the differential of the bracket with this new term, giving us (3x^2)/(x^3 + 2) as our overall differential