Calculate the PH of 32 mmol of HCl in 75cm^3 solution. Assume HCl fully dissociates.
32 mmol = 0.032 mol
75cm3 = 0.075dm3
n = c x v so c = n / v
c = 0.032mol/0.075 dm3 = 0.426moldm-3
pH = -log[H+]
pH = -log(0.426) = 0.37 (no units)
AP
Related Chemistry A Level answers
All answers ▸What is a coordinate bond?
Can you explain the trend in ionisation energy across the periodic table?
If we burn 3 moles of carbon in air (as per the equation), what mass (in grams) of carbon dioxide will be produced? What volume will this gas occupy at standard temperature and pressure?
State and explain the general trend in first ionisation energy across Period 3